Program to check whether given number is a perfect number or not
A number is a perfect number if it is equal to sum of all of it's positive divisors excluding itself
| 1 | /*Programme to check whether a given number is a perfect number or not*/ |
| 2 | #include <stdio.h> |
| 3 | #include <conio.h> |
| 4 | void main() |
| 5 | { |
| 6 | int num,i,sum=0; |
| 7 | |
| 8 | printf("Enter a Number to chech it's perfection and 0 to quit: "); |
| 9 | scanf("%d",&num); |
| 10 | |
| 11 | /*If vlaue entered by user is greater than 0 then continue else exit*/ |
| 12 | while(num!=0) |
| 13 | { |
| 14 | /*Calculate the sum of all the positive divisors*/ |
| 15 | for(i=1; i<num; i++) |
| 16 | { |
| 17 | if(num%i==0) |
| 18 | { |
| 19 | printf("%d + ",i); |
| 20 | sum=sum+i; |
| 21 | } |
| 22 | } |
| 23 | /*Check if the sum=num*/ |
| 24 | if(num==sum) |
| 25 | { |
| 26 | printf("= %d",sum); |
| 27 | printf("Perfet Number"); |
| 28 | } |
| 29 | else |
| 30 | { |
| 31 | printf("= %d",sum); |
| 32 | printf("Not a perfet Number"); |
| 33 | } |
| 34 | sum=0; |
| 35 | printf("Enter a Number to chech it's perfection and 0 to quit: "); |
| 36 | scanf("%d",&num); |
| 37 | } |
| 38 | } |
| 39 | |
by shilakant jha on 18-Aug-2012 01:06 pm About the author
Hi, I am Sachin Puri, I am a Programmer. Programming is my work and it is the thing i like to do most in my free time.
You can catch Sachin Puri at Google+
Hi, I am Sachin Puri, I am a Programmer. Programming is my work and it is the thing i like to do most in my free time.