Program to find all Armstrong numbers between 0 and 999
An Armstrong number of three digit is a number such that that sum
of the cubes of it's digits is equal to the number itself
For example 153 is an Armstrong number because cube of 1 is 1(1x1x1=1) + cube of 5 is 125(5*5*5=125) + cube of 3 is 27(3*3*3=27). Now add all the cubes 1+125+27=153 which is equals to number itself
| 1 | #include <stdio.h> |
| 2 | #include <conio.h> |
| 3 | #include <strings.h> |
| 4 | #include <math.h> |
| 5 | |
| 6 | int noOfDigits(int n){ |
| 7 | unsigned int number_of_digits = 0; |
| 8 | |
| 9 | do { |
| 10 | ++number_of_digits; |
| 11 | n /= 10; |
| 12 | } while (n); |
| 13 | |
| 14 | return number_of_digits; |
| 15 | } |
| 16 | |
| 17 | |
| 18 | int main() |
| 19 | { |
| 20 | int num,rem,qub,sum=0,i,len; |
| 21 | printf("Armstrong numbers between 0 to 999 are: "); |
| 22 | |
| 23 | for(i=0; i<=999; i++) |
| 24 | { |
| 25 | num=i; |
| 26 | sum=0; |
| 27 | len=noOfDigits(i); |
| 28 | while(num>0) |
| 29 | { |
| 30 | rem=num%10; |
| 31 | qub=pow(rem,len); |
| 32 | sum=sum+qub; |
| 33 | num=num/10; |
| 34 | } |
| 35 | if(sum==i) |
| 36 | { |
| 37 | printf("%d,",sum); |
| 38 | } |
| 39 | } |
| 40 | getch(); |
| 41 | } |
| 42 | |
| 43 | http://www.sachinpuri.com/Article/61/what_is_an_armstrong_number.html |
by Vish Ya Amrit Sitara on 14-Mar-2019 02:16 pm About the author
Hi, I am Sachin Puri, I am a Programmer. Programming is my work and it is the thing i like to do most in my free time.
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Hi, I am Sachin Puri, I am a Programmer. Programming is my work and it is the thing i like to do most in my free time.